bentuk akar √3(1-√3)
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[tex] = \sqrt{3} (1 - \sqrt{3} )[/tex]
[tex] = \sqrt{3} - {( \sqrt{3} )}^{2} [/tex]
[tex] = \sqrt{3} - 3[/tex]
Jawaban:
-3+√3
Penjelasan dengan langkah-langkah:
[tex] \sqrt{3} (1 - \sqrt{3} ) = \sqrt{3} .1 - \sqrt{3} . \sqrt{3} = \sqrt{3} - \sqrt{9} = \sqrt{3} - 3 = - 3 + \sqrt{3} [/tex]
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